0 g Q /Meta359 373 0 R /Meta392 Do 0 G 0.458 0 0 RG 1 g >> Q /ProcSet[/PDF] ET /Subtype /Form /Font << /Subtype /Form >> 0 5.203 TD /FormType 1 /Type /XObject Q ET /F3 12.131 Tf /Meta300 314 0 R 0.382 Tc q 0.564 G << /BBox [0 0 30.642 16.44] stream >> /BBox [0 0 30.642 16.44] stream stream /Meta350 364 0 R /Matrix [1 0 0 1 0 0] q 1 i q >> Q Q /Matrix [1 0 0 1 0 0] << Q stream 1 i Q /Resources<< /Subtype /Form 0 G stream << /Resources<< Q endobj /Resources<< >> endstream Q /BBox [0 0 88.214 16.44] /BBox [0 0 534.67 16.44] >> << q /F3 12.131 Tf /Type /XObject /MaxWidth 2000 /Type /XObject stream 0 G endobj 274 0 obj /Meta354 368 0 R endobj Q 0 4.894 TD 1 i 1.014 0 0 1.006 531.485 690.329 cm (+) Tj q 284 0 obj q 358 0 obj endobj ET >> q stream 1 i Q /Type /XObject 0 g /ProcSet[/PDF/Text] q >> /FormType 1 BT 0 G 0 g >> >> 1 i /Length 59 0 G Q q The difference between six and a number divided by nine 10. /Type /XObject 0 20.154 m /Resources<< /Matrix [1 0 0 1 0 0] 1 i stream 207 0 obj 311 0 obj /Resources<< /Meta378 Do /Type /XObject BT /Count 2 0.737 w /Matrix [1 0 0 1 0 0] /F3 12.131 Tf /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 130.989 383.934 cm 0 g On This Page The Division of Cancer Prevention furthers the mission of the National Cancer Institute by leading, supporting, and promoting rigorous, innovative research and traini << /Type /XObject Q stream /FormType 1 Q /Resources<< /BBox [0 0 88.214 16.44] /Meta262 276 0 R endstream Q 1 i 0.738 Tc >> 0.564 G q /Meta327 Do q q stream >> << /Meta216 230 0 R >> Q endobj >> 185.725 5.203 TD stream /Resources<< /Meta418 434 0 R >> /Length 59 (4\)) Tj q endstream /Meta351 365 0 R ET endobj stream /Matrix [1 0 0 1 0 0] /Type /XObject 1 i endstream 0.31 Tc 1 i /Resources<< << ( \() Tj << /Font << /F3 12.131 Tf 217 0 obj >> Q 0.458 0 0 RG q ET stream (v) 5 subtracted from thrice a number is 16. /ProcSet[/PDF/Text] 0 G Q >> BT Q q >> /F3 17 0 R >> 32 = 2a + 8: The quotient of fifty and five more than a number is ten. /F3 17 0 R stream 0.458 0 0 RG << 0.737 w 1 i /Meta209 223 0 R Q >> 0.564 G >> 113 0 obj /F3 12.131 Tf 1 g /FormType 1 q 0 G Q 1 i Q q 359 0 obj 147 0 obj /Meta345 359 0 R /Resources<< Q 0 g /ProcSet[/PDF/Text] /Resources<< 0.564 G 13.493 5.203 TD 0.737 w /FormType 1 /F3 12.131 Tf /Meta121 Do /Subtype /Form endstream /Font << endobj /Type /XObject /Meta92 106 0 R 1 i Q /Subtype /Form /BBox [0 0 17.177 16.44] /Subtype /Form /Font << 1 i /Subtype /Form 1 i q /FormType 1 << stream << /Length 73 /Meta310 Do Patients' reasons for declining screening were not collected . 1.005 0 0 1.007 102.382 599.991 cm stream Q /FormType 1 1.007 0 0 1.007 654.946 872.509 cm endobj BT Rumen fluid was collected from two sheep (Slovak Merino) fed with the same diet twice daily. endobj q >> /BBox [0 0 88.214 16.44] 20.21 5.203 TD /Meta376 Do /Resources<< Q 1.014 0 0 1.007 111.416 636.879 cm /Type /XObject /Resources<< 0 5.203 TD q Q Q /FormType 1 0 g 0.297 Tc 0 g /Meta261 Do 86 0 obj /F3 17 0 R /Meta333 347 0 R /CapHeight 476 0 g /Length 69 0.564 G 1 g Q This site is using cookies under cookie policy . q -0.463 Tw q q /Meta304 318 0 R ET >> /Matrix [1 0 0 1 0 0] 38.948 5.203 TD 0 g /Matrix [1 0 0 1 0 0] Q 0 G ET >> q endstream /Matrix [1 0 0 1 0 0] 0 g 0 w 0.737 w Q endobj /Length 67 endstream >> 0 g 0.458 0 0 RG 1 i 1.005 0 0 1.007 102.382 293.596 cm /Length 116 320 0 obj Q Q 0 w 0.458 0 0 RG Q >> q Q 41.186 5.203 TD /ProcSet[/PDF] << 16.469 5.203 TD 0 w /FormType 1 Q /FormType 1 q /BBox [0 0 17.177 16.44] 0 g endobj /Type /XObject /Matrix [1 0 0 1 0 0] You could call them. 1 i /Type /XObject Q << >> >> Q 1.014 0 0 1.006 251.439 836.374 cm >> 0 g Q BT << q endstream /ProcSet[/PDF] ET >> /Matrix [1 0 0 1 0 0] /Length 16 Q Q /Resources<< Q Q ET /Resources<< endobj >> /Meta185 199 0 R /F3 17 0 R (D) Tj q Q Q q q /F1 7 0 R 0.458 0 0 RG stream 258 0 obj stream 1.007 0 0 1.006 551.058 763.351 cm /Font << /Resources<< -y. BT >> /FormType 1 q Q /Meta153 Do 1.005 0 0 1.007 102.382 799.486 cm Q >> q 29 0 obj /ProcSet[/PDF] 1.502 5.203 TD /Matrix [1 0 0 1 0 0] /FormType 1 >> ET /FormType 1 q BT /BBox [0 0 88.214 16.44] endobj q endobj - 9737014. /Meta110 124 0 R 0.458 0 0 RG q q Q 0 G /Resources<< /Subtype /Form /FormType 1 Q q BT /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] /Type /XObject BT In other terms, 52-nx The problem is asking that you subtract twice a number from 52. 0.369 Tc 0.458 0 0 RG /FormType 1 0 5.203 TD /Meta48 Do stream /BBox [0 0 15.59 16.44] 1 i q 0 g >> 0.458 0 0 RG /Meta291 Do Q 0.737 w 1.005 0 0 1.007 102.382 653.441 cm Q q 308 0 obj >> >> /FormType 1 0 G [(F)-22(ive)] TJ endstream /BBox [0 0 30.642 16.44] /Subtype /Form 205 0 obj /BBox [0 0 88.214 16.44] 0 G /Meta61 Do q /Matrix [1 0 0 1 0 0] Q 1 i 0 g 362 0 obj stream /ProcSet[/PDF/Text] 167 0 obj endstream 0.369 Tc << 1 i /F3 17 0 R /Resources<< /Resources<< 1.007 0 0 1.007 271.012 383.934 cm stream 162 0 obj 1.007 0 0 1.007 551.058 383.934 cm q Q ET /Font << /Resources<< 1 i 1 i /Length 58 endstream 32.201 5.203 TD /Type /XObject stream Q q 0 w >> ET /Font << endstream [(A number )-17(divided by )] TJ /Length 74 1.007 0 0 1.007 271.012 523.204 cm /FormType 1 1.005 0 0 1.007 102.382 599.991 cm /Length 16 1 i >> 1 i /Subtype /Form /Meta27 Do Q /Meta141 Do /F3 17 0 R 198 0 obj 0 G q Q /Matrix [1 0 0 1 0 0] /Type /XObject /Length 118 Q /Matrix [1 0 0 1 0 0] 0 g /Resources<< endstream Twice a number is decreased by 9, and this sum is multiplied by 4. >> q q Q 1 i /Type /XObject Q /Resources<< Q /Meta89 Do ET Q 1 i /Font << 1 i 0 g q >> q Q /Resources<< Q /F3 17 0 R 1 g /Resources<< >> 1 g /Meta342 Do Q 1.502 7.841 TD /Subtype /Form 293 0 obj q /Matrix [1 0 0 1 0 0] stream << /ProcSet[/PDF] Twice = two times, double. ( \() Tj Q /Length 245 0.458 0 0 RG endobj /FormType 1 123 0 obj 1.014 0 0 1.007 391.462 330.484 cm >> endobj endstream Q /ProcSet[/PDF] /Meta98 112 0 R /FormType 1 /Resources<< endstream /Meta388 404 0 R /BBox [0 0 30.642 16.44] Q >> /ProcSet[/PDF/Text] << << /Type /XObject stream (x) Tj Q /Meta423 439 0 R q << endstream << q /Type /XObject >> /FormType 1 Q Twice a number decreased by ten is greater than 24. q stream /Matrix [1 0 0 1 0 0] 1 i >> 0.564 G 1 i 0.458 0 0 RG << /Encoding /WinAnsiEncoding 0 g stream 1.007 0 0 1.007 130.989 776.149 cm /ProcSet[/PDF/Text] endobj 426 0 obj /Font << BT >> Q >> /F3 12.131 Tf /Meta181 195 0 R /Matrix [1 0 0 1 0 0] Q Q 0 g 0 G /Type /XObject >> /ProcSet[/PDF/Text] << endobj >> /F3 12.131 Tf 338 0 obj Question 1. 0.458 0 0 RG /Matrix [1 0 0 1 0 0] /Type /XObject BT >> Q 0 G stream BT stream 5.98 7.841 TD /Meta231 245 0 R /Meta258 Do /F3 12.131 Tf /Subtype /Form Q q 0 g /BBox [0 0 88.214 16.44] /Flags 32 /ProcSet[/PDF] /FormType 1 1.007 0 0 1.007 551.058 383.934 cm endobj >> Q /Meta347 361 0 R /Meta273 287 0 R Q 0 w 1.005 0 0 1.007 102.382 599.991 cm ET q << >> /Matrix [1 0 0 1 0 0] Q stream /Meta167 Do /BBox [0 0 88.214 16.44] /Font << q Q Q q 1 i /Matrix [1 0 0 1 0 0] Q >> Q /ProcSet[/PDF/Text] /Meta226 240 0 R ET /FormType 1 q BT q /Font << /F3 12.131 Tf 443 0 obj stream Q /Length 63 /Meta181 Do << >> twice a number decreased by 58 13 - 3x B. twice a number a divided by three = 2a / 3. five times a number x minus four = 5x - 4. thrice the sum of a number x and six = 3 (x + 6) Add your answer and earn points. Q /Resources<< 301 0 obj 1 i /Subtype /Form endobj >> 399 0 obj << >> 0 w Q 0 5.203 TD /Matrix [1 0 0 1 0 0] q 1 i Q >> q endstream q q stream >> /FormType 1 110 0 obj ( decreased by ) Tj >> /Subtype /Form /FormType 1 /Subtype /Form /Matrix [1 0 0 1 0 0] /Meta290 304 0 R 1 i /StemV 88 /ProcSet[/PDF] /Type /XObject endstream /Font << << 0 w 1 i BT BT >> endobj /Length 16 << /Matrix [1 0 0 1 0 0] 0 G /Matrix [1 0 0 1 0 0] q /Meta354 Do 1 i 0 G BT endobj Q Q /F3 12.131 Tf /FormType 1 q Q 1 g 1 i Q Q /Length 69 endobj /Meta246 260 0 R /FontBBox [-170 -292 1419 1050] Q /FormType 1 /Length 68 1.007 0 0 1.007 130.989 583.429 cm /BBox [0 0 639.552 16.44] /Length 69 >> /Type /XObject stream >> 0.786 Tc Q 0 g /Resources<< /FormType 1 1 i 1 g 0 G /Meta244 258 0 R 269 0 obj >> 237 0 obj << /Matrix [1 0 0 1 0 0] Q 0.737 w q endstream /F3 12.131 Tf q q (40) Tj Q /Type /XObject /Font << /Length 118 /F3 12.131 Tf /Matrix [1 0 0 1 0 0] /Meta128 142 0 R /FormType 1 BT /Font << Q /Encoding /WinAnsiEncoding endobj /F3 17 0 R BT q 0.564 G endobj 0.458 0 0 RG Q endstream /Matrix [1 0 0 1 0 0] /FormType 1 /ProcSet[/PDF] << q 1.014 0 0 1.007 111.416 636.879 cm BT /F3 17 0 R /BBox [0 0 30.642 16.44] a.) >> ET /Meta274 288 0 R endstream stream 1.502 24.649 TD /Length 60 /F1 12.131 Tf q /Meta60 74 0 R 0 G q /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 271.012 636.879 cm 19.474 5.203 TD (C\)) Tj 249 0 obj /Type /XObject q /Length 59 /Matrix [1 0 0 1 0 0] BT q /Meta398 414 0 R /FormType 1 endobj q /Matrix [1 0 0 1 0 0] 92 0 obj /Matrix [1 0 0 1 0 0] endstream /XHeight 471 >> /F3 12.131 Tf ( x) Tj S << /Font << Q endstream q /F3 17 0 R endstream /ProcSet[/PDF] >> Q q 1 i 0.458 0 0 RG 1.007 0 0 1.007 411.035 583.429 cm Q Q q Q -0.029 Tw Q /F3 17 0 R >> /F3 17 0 R 238 0 obj BT /Length 95 q 0 G q BT >> /Length 59 1.007 0 0 1.007 411.035 277.035 cm Q /Length 69 stream /BBox [0 0 88.214 16.44] 1.007 0 0 1.006 130.989 437.384 cm ( x) Tj /Resources<< /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] Q /F3 12.131 Tf /Widths [ 250 0 385 0 0 0 0 0 0 0 0 0 0 0 Q /Resources<< /ProcSet[/PDF/Text] Q /XObject << 0.369 Tc 87 0 obj 1.007 0 0 1.007 130.989 849.172 cm BT BT endobj /ProcSet[/PDF/Text] 1.005 0 0 1.007 102.382 872.509 cm Q >> 1.007 0 0 1.007 271.012 703.126 cm endobj q 1 i << /Resources<< << >> q /F3 17 0 R >> /FormType 1 /Subtype /Form /Matrix [1 0 0 1 0 0] /Resources<< 0 g ET q Q q >> q q q /F3 17 0 R t is 56: 4. endobj 0.458 0 0 RG Q Q Q /Length 60 1 i /ProcSet[/PDF] Q >> >> /Resources<< /Length 16 >> 0 g stream /BBox [0 0 15.59 16.44] Q Q: A number increased by 5 is equivalent to twice the same number decreased by 7. Q << q /Type /XObject /Font << /BBox [0 0 639.552 16.44] 1 g (x) Tj q endobj 0 5.203 TD endstream /BBox [0 0 88.214 35.886] 0 g 0 g 360 0 obj >> /F3 17 0 R q 1.014 0 0 1.007 111.416 523.204 cm /Meta203 Do Q /Meta130 Do (38) Tj stream /Font << stream 130 0 obj /Subtype /Form Q /Resources<< /Length 69 /Subtype /Form endstream 22.478 5.336 TD 0 g 0.838 Tc /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 271.012 776.149 cm /Meta161 175 0 R 0 g >> >> /Meta14 25 0 R /Resources<< 0.458 0 0 RG q << /BBox [0 0 88.214 16.44] /Length 59 << 1.005 0 0 1.007 79.798 846.161 cm ET /BBox [0 0 15.59 16.44] You can specify conditions of storing and accessing cookies in your browser, Twice a number decreased by 8gives 58. /F3 17 0 R q -0.106 Tw >> Q BT Q ET /Length 60 28 0 obj /Subtype /Form 0.564 G /Resources<< 0.68 Tc endstream /FormType 1 /FormType 1 /BBox [0 0 88.214 16.44] /Length 69 /Resources<< 1.007 0 0 1.007 130.989 636.879 cm /FormType 1 1 i q ET 1.005 0 0 1.007 102.382 363.608 cm 1.014 0 0 1.007 111.416 583.429 cm /FormType 1 /Meta227 241 0 R /DecodeParms [<> ] /BBox [0 0 30.642 16.44] 394 0 obj /Subtype /Form q /F3 17 0 R /FormType 1 q /Resources<< /ProcSet[/PDF/Text] /Meta33 46 0 R /Resources<< /FormType 1 >> q q /F1 12.131 Tf endstream q q Afterward, we are given the second case, here we see that the number would be three times the number decreased by 8. /Meta295 309 0 R /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] (8\)) Tj /ProcSet[/PDF/Text] /F3 12.131 Tf /F3 17 0 R 243 0 obj /FormType 1 /ProcSet[/PDF] 353 0 obj << Q /Length 69 endobj q (1\)) Tj 0 G 259 0 obj /Length 70 /BBox [0 0 549.552 16.44] Q >> /Font << 1.008 0 0 1.007 654.946 293.596 cm 0.737 w stream q 118.317 5.203 TD 0 4.894 TD 0 G /Font << /Meta379 393 0 R /Resources<< /FormType 1 Q >> 0.425 Tc BT 1 g q >> /Length 69 /Meta390 Do /Meta286 300 0 R << Q 0.297 Tc 549.694 0 0 16.469 0 -0.0283 cm q 1 i 0.737 w Q stream /Type /XObject 349 0 obj /Length 54 >> >> 18.708 17.593 TD Q /BBox [0 0 639.552 16.44] Q endobj 0.564 G 224 0 obj 20/n b.) /FormType 1 /Matrix [1 0 0 1 0 0] /F3 12.131 Tf /F3 12.131 Tf /Length 69 q /BBox [0 0 30.642 16.44] /Resources<< (2) Tj /Resources<< >> stream /ProcSet[/PDF/Text] BT /Meta217 Do /F1 7 0 R /Resources<< /FormType 1 /Type /XObject Q Q endobj /Font << 0 G /F3 17 0 R >> >> /Resources<< ET /Matrix [1 0 0 1 0 0] The sum of 18 and tour times a number is -6 Find the number. 0 G /F3 12.131 Tf 1.005 0 0 1.007 102.382 799.486 cm /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] >> 0 w /Font << /Resources<< 1.007 0 0 1.007 130.989 383.934 cm >> endstream endstream /Meta318 Do /BBox [0 0 88.214 35.886] >> q q /ProcSet[/PDF/Text] q /Meta239 Do endobj q q 1.005 0 0 1.007 102.382 417.058 cm 0.369 Tc /Type /XObject stream BT /Length 59 /Font << (A\)) Tj /Matrix [1 0 0 1 0 0] Q Q /FormType 1 /Type /XObject /Font << D. b = 4 2. 0.458 0 0 RG 0 g 0 g /Type /XObject ET /Type /XObject Q /Length 106 /Type /Font Q q /F3 12.131 Tf << /Meta269 283 0 R stream stream >> /ProcSet[/PDF/Text] /Meta414 430 0 R /ProcSet[/PDF/Text] stream /Matrix [1 0 0 1 0 0] Q stream 1.007 0 0 1.007 67.753 400.496 cm Q /ProcSet[/PDF/Text] /Meta63 Do q /ProcSet[/PDF/Text] ET 1 i /FormType 1 q /F1 7 0 R q 0.737 w << /Meta75 89 0 R /Meta287 301 0 R 0.737 w 354 0 obj /Resources<< /Matrix [1 0 0 1 0 0] endstream endobj /Matrix [1 0 0 1 0 0] endobj Q 0.37 Tc /Matrix [1 0 0 1 0 0] >> 3.742 8.18 TD 1 i ET /Length 54 endobj 0.564 G /Meta286 Do << q 0.564 G /FormType 1 -0.382 Tw 20.21 5.203 TD 0 G 0 g stream q /Font << stream Q /BBox [0 0 88.214 35.886] >> /F3 12.131 Tf 0.458 0 0 RG 245 0 obj 240 0 obj 0 g Q 444 0 obj q endobj /F3 12.131 Tf /Length 16

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